5(x-2)-3(-x+2)=-(x-1)+1

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Solution for 5(x-2)-3(-x+2)=-(x-1)+1 equation: 



5(x-2)-3(-x+2)=-(x-1)+1

We move all terms to the left:

5(x-2)-3(-x+2)-(-(x-1)+1)=0

We add all the numbers together, and all the variables

5(x-2)-3(-1x+2)-(-(x-1)+1)=0

We multiply parentheses

5x+3x-(-(x-1)+1)-10-6=0



We calculate terms in parentheses: -(-(x-1)+1), so:

-(x-1)+1

We get rid of parentheses

-x+1+1

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We add all the numbers together, and all the variables

8x-(-1x+2)-16=0

We get rid of parentheses

8x+1x-2-16=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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