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5(x-2)-3x=(x-5)
We move all terms to the left:
5(x-2)-3x-((x-5))=0
We add all the numbers together, and all the variables
-3x+5(x-2)-((x-5))=0
We multiply parentheses
-3x+5x-((x-5))-10=0
We calculate terms in parentheses: -((x-5)), so:We add all the numbers together, and all the variables
(x-5)
We get rid of parentheses
x-5
Back to the equation:
-(x-5)
2x-(x-5)-10=0
We get rid of parentheses
2x-x+5-10=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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