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5(x-2)=2(2x+)
We move all terms to the left:
5(x-2)-(2(2x+))=0
We add all the numbers together, and all the variables
5(x-2)-(2(+2x))=0
We multiply parentheses
5x-(2(+2x))-10=0
We calculate terms in parentheses: -(2(+2x)), so:We add all the numbers together, and all the variables
2(+2x)
We multiply parentheses
4x
Back to the equation:
-(4x)
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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