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5(x-2)=2(x-3)
We move all terms to the left:
5(x-2)-(2(x-3))=0
We multiply parentheses
5x-(2(x-3))-10=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
5x-2x+6-10=0
We add all the numbers together, and all the variables
3x-4=0
We move all terms containing x to the left, all other terms to the right
3x=4
x=4/3
x=1+1/3
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