5(x-2)=21-5(x-2)

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Solution for 5(x-2)=21-5(x-2) equation: 



5(x-2)=21-5(x-2)

We move all terms to the left:

5(x-2)-(21-5(x-2))=0

We multiply parentheses

5x-(21-5(x-2))-10=0



We calculate terms in parentheses: -(21-5(x-2)), so:

21-5(x-2)

determiningTheFunctionDomain
-5(x-2)+21

We multiply parentheses

-5x+10+21

We add all the numbers together, and all the variables

-5x+31

Back to the equation:

-(-5x+31)



We get rid of parentheses

5x+5x-31-10=0

We add all the numbers together, and all the variables

10x-41=0

We move all terms containing x to the left, all other terms to the right

10x=41

x=41/10

x=4+1/10

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