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5(x-2)=4(1/2x+2)
We move all terms to the left:
5(x-2)-(4(1/2x+2))=0
Domain of the equation: 2x+2))!=0We multiply parentheses
x∈R
5x-(4(1/2x+2))-10=0
We multiply all the terms by the denominator
5x*2x-10*2x+2))-(4(1+2))=0
We add all the numbers together, and all the variables
5x*2x-10*2x+2))-(43)=0
We add all the numbers together, and all the variables
5x*2x-10*2x=0
Wy multiply elements
10x^2-20x=0
a = 10; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·10·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*10}=\frac{40}{20} =2 $
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