5(x-2)=4(2x+5);x

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Solution for 5(x-2)=4(2x+5);x equation: 



5(x-2)=4(2x+5)x

We move all terms to the left:

5(x-2)-(4(2x+5)x)=0

We multiply parentheses

5x-(4(2x+5)x)-10=0



We calculate terms in parentheses: -(4(2x+5)x), so:

4(2x+5)x

We multiply parentheses

8x^2+20x

Back to the equation:

-(8x^2+20x)



We get rid of parentheses

-8x^2+5x-20x-10=0

We add all the numbers together, and all the variables

-8x^2-15x-10=0

a = -8; b = -15; c = -10;
Δ = b2-4ac
Δ = -152-4·(-8)·(-10)
Δ = -95
Delta is less than zero, so there is no solution for the equation

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