5(x-3)(x+1)=0

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Solution for 5(x-3)(x+1)=0 equation:



5(x-3)(x+1)=0
We multiply parentheses ..
5(+x^2+x-3x-3)=0
We multiply parentheses
5x^2+5x-15x-15=0
We add all the numbers together, and all the variables
5x^2-10x-15=0
a = 5; b = -10; c = -15;
Δ = b2-4ac
Δ = -102-4·5·(-15)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-20}{2*5}=\frac{-10}{10} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+20}{2*5}=\frac{30}{10} =3 $

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