5(x-3)+10x-12+2(+2x+3)=12(x-1)-5(6-2x)

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Solution for 5(x-3)+10x-12+2(+2x+3)=12(x-1)-5(6-2x) equation: 



5(x-3)+10x-12+2(+2x+3)=12(x-1)-5(6-2x)

We move all terms to the left:

5(x-3)+10x-12+2(+2x+3)-(12(x-1)-5(6-2x))=0

We add all the numbers together, and all the variables

5(x-3)+10x+2(2x+3)-(12(x-1)-5(-2x+6))-12=0

We add all the numbers together, and all the variables

10x+5(x-3)+2(2x+3)-(12(x-1)-5(-2x+6))-12=0

We multiply parentheses

10x+5x+4x-(12(x-1)-5(-2x+6))-15+6-12=0



We calculate terms in parentheses: -(12(x-1)-5(-2x+6)), so:

12(x-1)-5(-2x+6)

We multiply parentheses

12x+10x-12-30

We add all the numbers together, and all the variables

22x-42

Back to the equation:

-(22x-42)



We add all the numbers together, and all the variables

19x-(22x-42)-21=0

We get rid of parentheses

19x-22x+42-21=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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