5(x-3)+11=4(x+2)

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Solution for 5(x-3)+11=4(x+2) equation: 



5(x-3)+11=4(x+2)

We move all terms to the left:

5(x-3)+11-(4(x+2))=0

We multiply parentheses

5x-(4(x+2))-15+11=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

5x-(4x+8)-4=0

We get rid of parentheses

5x-4x-8-4=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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