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5(x-3)+11=4(x+2)
We move all terms to the left:
5(x-3)+11-(4(x+2))=0
We multiply parentheses
5x-(4(x+2))-15+11=0
We calculate terms in parentheses: -(4(x+2)), so:We add all the numbers together, and all the variables
4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
5x-(4x+8)-4=0
We get rid of parentheses
5x-4x-8-4=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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