5(x-3)+1=6x-2

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Solution for 5(x-3)+1=6x-2 equation: 



5(x-3)+1=6x-2

We move all terms to the left:

5(x-3)+1-(6x-2)=0

We multiply parentheses

5x-(6x-2)-15+1=0

We get rid of parentheses

5x-6x+2-15+1=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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