5(x-3)+2(x+4)=21

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Solution for 5(x-3)+2(x+4)=21 equation: 



5(x-3)+2(x+4)=21

We move all terms to the left:

5(x-3)+2(x+4)-(21)=0

We multiply parentheses

5x+2x-15+8-21=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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