5(x-3)+2(x-7)-3(x+3)=2(x-4)

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Solution for 5(x-3)+2(x-7)-3(x+3)=2(x-4) equation: 



5(x-3)+2(x-7)-3(x+3)=2(x-4)

We move all terms to the left:

5(x-3)+2(x-7)-3(x+3)-(2(x-4))=0

We multiply parentheses

5x+2x-3x-(2(x-4))-15-14-9=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

4x-(2x-8)-38=0

We get rid of parentheses

4x-2x+8-38=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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