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5(x-3)+2=3x+2(-4+x)
We move all terms to the left:
5(x-3)+2-(3x+2(-4+x))=0
We add all the numbers together, and all the variables
5(x-3)-(3x+2(x-4))+2=0
We multiply parentheses
5x-(3x+2(x-4))-15+2=0
We calculate terms in parentheses: -(3x+2(x-4)), so:We add all the numbers together, and all the variables
3x+2(x-4)
We multiply parentheses
3x+2x-8
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
5x-(5x-8)-13=0
We get rid of parentheses
5x-5x+8-13=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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