5(x-3)+2=x+5(x+4)

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Solution for 5(x-3)+2=x+5(x+4) equation: 



5(x-3)+2=x+5(x+4)

We move all terms to the left:

5(x-3)+2-(x+5(x+4))=0

We multiply parentheses

5x-(x+5(x+4))-15+2=0



We calculate terms in parentheses: -(x+5(x+4)), so:

x+5(x+4)

We multiply parentheses

x+5x+20

We add all the numbers together, and all the variables

6x+20

Back to the equation:

-(6x+20)



We add all the numbers together, and all the variables

5x-(6x+20)-13=0

We get rid of parentheses

5x-6x-20-13=0

We add all the numbers together, and all the variables

-1x-33=0

We move all terms containing x to the left, all other terms to the right

-x=33

x=33/-1

x=-33

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