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5(x-3)+2x=(x-4)+4x
We move all terms to the left:
5(x-3)+2x-((x-4)+4x)=0
We add all the numbers together, and all the variables
2x+5(x-3)-((x-4)+4x)=0
We multiply parentheses
2x+5x-((x-4)+4x)-15=0
We calculate terms in parentheses: -((x-4)+4x), so:We add all the numbers together, and all the variables
(x-4)+4x
We add all the numbers together, and all the variables
4x+(x-4)
We get rid of parentheses
4x+x-4
We add all the numbers together, and all the variables
5x-4
Back to the equation:
-(5x-4)
7x-(5x-4)-15=0
We get rid of parentheses
7x-5x+4-15=0
We add all the numbers together, and all the variables
2x-11=0
We move all terms containing x to the left, all other terms to the right
2x=11
x=11/2
x=5+1/2
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