5(x-3)+2x=7(x+2)-29

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Solution for 5(x-3)+2x=7(x+2)-29 equation: 



5(x-3)+2x=7(x+2)-29

We move all terms to the left:

5(x-3)+2x-(7(x+2)-29)=0

We add all the numbers together, and all the variables

2x+5(x-3)-(7(x+2)-29)=0

We multiply parentheses

2x+5x-(7(x+2)-29)-15=0



We calculate terms in parentheses: -(7(x+2)-29), so:

7(x+2)-29

We multiply parentheses

7x+14-29

We add all the numbers together, and all the variables

7x-15

Back to the equation:

-(7x-15)



We add all the numbers together, and all the variables

7x-(7x-15)-15=0

We get rid of parentheses

7x-7x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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