5(x-3)+3(x+1)-2x=9(x+2)+4(x-1)-7x

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Solution for 5(x-3)+3(x+1)-2x=9(x+2)+4(x-1)-7x equation: 



5(x-3)+3(x+1)-2x=9(x+2)+4(x-1)-7x

We move all terms to the left:

5(x-3)+3(x+1)-2x-(9(x+2)+4(x-1)-7x)=0

We add all the numbers together, and all the variables

-2x+5(x-3)+3(x+1)-(9(x+2)+4(x-1)-7x)=0

We multiply parentheses

-2x+5x+3x-(9(x+2)+4(x-1)-7x)-15+3=0



We calculate terms in parentheses: -(9(x+2)+4(x-1)-7x), so:

9(x+2)+4(x-1)-7x

We add all the numbers together, and all the variables

-7x+9(x+2)+4(x-1)

We multiply parentheses

-7x+9x+4x+18-4

We add all the numbers together, and all the variables

6x+14

Back to the equation:

-(6x+14)



We add all the numbers together, and all the variables

6x-(6x+14)-12=0

We get rid of parentheses

6x-6x-14-12=0

We add all the numbers together, and all the variables

-26!=0

There is no solution for this equation

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