5(x-3)+6(1-x)=4x+12-5(x-2)

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Solution for 5(x-3)+6(1-x)=4x+12-5(x-2) equation: 



5(x-3)+6(1-x)=4x+12-5(x-2)

We move all terms to the left:

5(x-3)+6(1-x)-(4x+12-5(x-2))=0

We add all the numbers together, and all the variables

5(x-3)+6(-1x+1)-(4x+12-5(x-2))=0

We multiply parentheses

5x-6x-(4x+12-5(x-2))-15+6=0



We calculate terms in parentheses: -(4x+12-5(x-2)), so:

4x+12-5(x-2)

determiningTheFunctionDomain
4x-5(x-2)+12

We multiply parentheses

4x-5x+10+12

We add all the numbers together, and all the variables

-1x+22

Back to the equation:

-(-1x+22)



We add all the numbers together, and all the variables

-1x-(-1x+22)-9=0

We get rid of parentheses

-1x+1x-22-9=0

We add all the numbers together, and all the variables

-31!=0

There is no solution for this equation

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