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5(x-3)+6=9x-(4x+5)-4
We move all terms to the left:
5(x-3)+6-(9x-(4x+5)-4)=0
We multiply parentheses
5x-(9x-(4x+5)-4)-15+6=0
We calculate terms in parentheses: -(9x-(4x+5)-4), so:We add all the numbers together, and all the variables
9x-(4x+5)-4
We get rid of parentheses
9x-4x-5-4
We add all the numbers together, and all the variables
5x-9
Back to the equation:
-(5x-9)
5x-(5x-9)-9=0
We get rid of parentheses
5x-5x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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