5(x-3)+7(2-x)-4(2x+7)-3x+2=11-8(x-7)+4x-(6-5)+8-2x

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Solution for 5(x-3)+7(2-x)-4(2x+7)-3x+2=11-8(x-7)+4x-(6-5)+8-2x equation: 



5(x-3)+7(2-x)-4(2x+7)-3x+2=11-8(x-7)+4x-(6-5)+8-2x

We move all terms to the left:

5(x-3)+7(2-x)-4(2x+7)-3x+2-(11-8(x-7)+4x-(6-5)+8-2x)=0

We add all the numbers together, and all the variables

5(x-3)+7(-1x+2)-4(2x+7)-3x-(11-8(x-7)+4x-1+8-2x)+2=0

We add all the numbers together, and all the variables

-3x+5(x-3)+7(-1x+2)-4(2x+7)-(11-8(x-7)+4x-1+8-2x)+2=0

We multiply parentheses

-3x+5x-7x-8x-(11-8(x-7)+4x-1+8-2x)-15+14-28+2=0



We calculate terms in parentheses: -(11-8(x-7)+4x-1+8-2x), so:

11-8(x-7)+4x-1+8-2x

determiningTheFunctionDomain
-8(x-7)+4x-2x+11-1+8

We add all the numbers together, and all the variables

2x-8(x-7)+18

We multiply parentheses

2x-8x+56+18

We add all the numbers together, and all the variables

-6x+74

Back to the equation:

-(-6x+74)



We add all the numbers together, and all the variables

-13x-(-6x+74)-27=0

We get rid of parentheses

-13x+6x-74-27=0

We add all the numbers together, and all the variables

-7x-101=0

We move all terms containing x to the left, all other terms to the right

-7x=101

x=101/-7

x=-14+3/7

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