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5(x-3)-10=2(x-5)
We move all terms to the left:
5(x-3)-10-(2(x-5))=0
We multiply parentheses
5x-(2(x-5))-15-10=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
5x-(2x-10)-25=0
We get rid of parentheses
5x-2x+10-25=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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