5(x-3)-2(x+3)=2(x-4)

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Solution for 5(x-3)-2(x+3)=2(x-4) equation: 



5(x-3)-2(x+3)=2(x-4)

We move all terms to the left:

5(x-3)-2(x+3)-(2(x-4))=0

We multiply parentheses

5x-2x-(2(x-4))-15-6=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

3x-(2x-8)-21=0

We get rid of parentheses

3x-2x+8-21=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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