5(x-3)-2x=4+(3-x)=12

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Solution for 5(x-3)-2x=4+(3-x)=12 equation: 



5(x-3)-2x=4+(3-x)=12

We move all terms to the left:

5(x-3)-2x-(4+(3-x))=0

We add all the numbers together, and all the variables

5(x-3)-2x-(4+(-1x+3))=0

We add all the numbers together, and all the variables

-2x+5(x-3)-(4+(-1x+3))=0

We multiply parentheses

-2x+5x-(4+(-1x+3))-15=0



We calculate terms in parentheses: -(4+(-1x+3)), so:

4+(-1x+3)

determiningTheFunctionDomain
(-1x+3)+4

We get rid of parentheses

-1x+3+4

We add all the numbers together, and all the variables

-1x+7

Back to the equation:

-(-1x+7)



We add all the numbers together, and all the variables

3x-(-1x+7)-15=0

We get rid of parentheses

3x+1x-7-15=0

We add all the numbers together, and all the variables

4x-22=0

We move all terms containing x to the left, all other terms to the right

4x=22

x=22/4

x=5+1/2

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