5(x-3)-4(x+12)=2+3(1-2x)

Solution for 5(x-3)-4(x+12)=2+3(1-2x) equation:

5(x-3)-4(x+12)=2+3(1-2x)

We move all terms to the left:

5(x-3)-4(x+12)-(2+3(1-2x))=0

We add all the numbers together, and all the variables

5(x-3)-4(x+12)-(2+3(-2x+1))=0

We multiply parentheses

5x-4x-(2+3(-2x+1))-15-48=0


We calculate terms in parentheses: -(2+3(-2x+1)), so:

2+3(-2x+1)

determiningTheFunctionDomain
3(-2x+1)+2

We multiply parentheses

-6x+3+2

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)


We add all the numbers together, and all the variables

x-(-6x+5)-63=0

We get rid of parentheses

x+6x-5-63=0

We add all the numbers together, and all the variables

7x-68=0

We move all terms containing x to the left, all other terms to the right

7x=68

x=68/7

x=9+5/7