5(x-3)-4(x-2)=8+3(1/3-x)

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Solution for 5(x-3)-4(x-2)=8+3(1/3-x) equation: 



5(x-3)-4(x-2)=8+3(1/3-x)

We move all terms to the left:

5(x-3)-4(x-2)-(8+3(1/3-x))=0



Domain of the equation: 3-x))!=0

We move all terms containing x to the left, all other terms to the right

-x))!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

5(x-3)-4(x-2)-(8+3(-1x+1/3))=0

We multiply parentheses

5x-4x-(8+3(-1x+1/3))-15+8=0

We multiply all the terms by the denominator


5x*3))-4x*3))-(8+3(-1x+1-15*3))+8*3))=0

We add all the numbers together, and all the variables

5x*3))-4x*3))-(8+3(-1x-44))+8*3))=0

Wy multiply elements

135x^4=0

We do not support expression: x^4

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