5(x-3)-4=(x+4)/5-2x+1

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Solution for 5(x-3)-4=(x+4)/5-2x+1 equation: 



5(x-3)-4=(x+4)/5-2x+1

We move all terms to the left:

5(x-3)-4-((x+4)/5-2x+1)=0



Domain of the equation: 5-2x+1)!=0

We move all terms containing x to the left, all other terms to the right

-2x+1)!=-5

x∈R



We multiply parentheses

5x-((x+4)/5-2x+1)-15-4=0

We multiply all the terms by the denominator


5x*5-2x+1)-((x+4)-2x+1)-4*5-2x+1)-15*5=0

We add all the numbers together, and all the variables

-4x+5x*5+1)-((x+4)+1)-4*5-2x+1)-15*5=0

Wy multiply elements

-4x+25x+1)-((x+4)+1)-4*5-2x+1)-15*5=0

We add all the numbers together, and all the variables

21x+1)-((x+4)+1)-4*5-2x+1)-15*5=0

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