5(x-3)-6=2(x+1)+4

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Solution for 5(x-3)-6=2(x+1)+4 equation: 



5(x-3)-6=2(x+1)+4

We move all terms to the left:

5(x-3)-6-(2(x+1)+4)=0

We multiply parentheses

5x-(2(x+1)+4)-15-6=0



We calculate terms in parentheses: -(2(x+1)+4), so:

2(x+1)+4

We multiply parentheses

2x+2+4

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

5x-(2x+6)-21=0

We get rid of parentheses

5x-2x-6-21=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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