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5(x-3)=12-(5x+7)
We move all terms to the left:
5(x-3)-(12-(5x+7))=0
We multiply parentheses
5x-(12-(5x+7))-15=0
We calculate terms in parentheses: -(12-(5x+7)), so:We get rid of parentheses
12-(5x+7)
determiningTheFunctionDomain -(5x+7)+12
We get rid of parentheses
-5x-7+12
We add all the numbers together, and all the variables
-5x+5
Back to the equation:
-(-5x+5)
5x+5x-5-15=0
We add all the numbers together, and all the variables
10x-20=0
We move all terms containing x to the left, all other terms to the right
10x=20
x=20/10
x=2
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