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5(x-3)=2+2(x-3)
We move all terms to the left:
5(x-3)-(2+2(x-3))=0
We multiply parentheses
5x-(2+2(x-3))-15=0
We calculate terms in parentheses: -(2+2(x-3)), so:We get rid of parentheses
2+2(x-3)
determiningTheFunctionDomain 2(x-3)+2
We multiply parentheses
2x-6+2
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
5x-2x+4-15=0
We add all the numbers together, and all the variables
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3
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