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5(x-3)=2x-3(x+1)
We move all terms to the left:
5(x-3)-(2x-3(x+1))=0
We multiply parentheses
5x-(2x-3(x+1))-15=0
We calculate terms in parentheses: -(2x-3(x+1)), so:We get rid of parentheses
2x-3(x+1)
We multiply parentheses
2x-3x-3
We add all the numbers together, and all the variables
-1x-3
Back to the equation:
-(-1x-3)
5x+1x+3-15=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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