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5(x-3)=3(2x+5)
We move all terms to the left:
5(x-3)-(3(2x+5))=0
We multiply parentheses
5x-(3(2x+5))-15=0
We calculate terms in parentheses: -(3(2x+5)), so:We get rid of parentheses
3(2x+5)
We multiply parentheses
6x+15
Back to the equation:
-(6x+15)
5x-6x-15-15=0
We add all the numbers together, and all the variables
-1x-30=0
We move all terms containing x to the left, all other terms to the right
-x=30
x=30/-1
x=-30
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