5(x-3)=3(x+4)x

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Solution for 5(x-3)=3(x+4)x equation: 



5(x-3)=3(x+4)x

We move all terms to the left:

5(x-3)-(3(x+4)x)=0

We multiply parentheses

5x-(3(x+4)x)-15=0



We calculate terms in parentheses: -(3(x+4)x), so:

3(x+4)x

We multiply parentheses

3x^2+12x

Back to the equation:

-(3x^2+12x)



We get rid of parentheses

-3x^2+5x-12x-15=0

We add all the numbers together, and all the variables

-3x^2-7x-15=0

a = -3; b = -7; c = -15;
Δ = b2-4ac
Δ = -72-4·(-3)·(-15)
Δ = -131
Delta is less than zero, so there is no solution for the equation

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