5(x-3)=4(x+3)+5(x+1)

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Solution for 5(x-3)=4(x+3)+5(x+1) equation: 



5(x-3)=4(x+3)+5(x+1)

We move all terms to the left:

5(x-3)-(4(x+3)+5(x+1))=0

We multiply parentheses

5x-(4(x+3)+5(x+1))-15=0



We calculate terms in parentheses: -(4(x+3)+5(x+1)), so:

4(x+3)+5(x+1)

We multiply parentheses

4x+5x+12+5

We add all the numbers together, and all the variables

9x+17

Back to the equation:

-(9x+17)



We get rid of parentheses

5x-9x-17-15=0

We add all the numbers together, and all the variables

-4x-32=0

We move all terms containing x to the left, all other terms to the right

-4x=32

x=32/-4

x=-8

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