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5(x-3)=7(3x+2)
We move all terms to the left:
5(x-3)-(7(3x+2))=0
We multiply parentheses
5x-(7(3x+2))-15=0
We calculate terms in parentheses: -(7(3x+2)), so:We get rid of parentheses
7(3x+2)
We multiply parentheses
21x+14
Back to the equation:
-(21x+14)
5x-21x-14-15=0
We add all the numbers together, and all the variables
-16x-29=0
We move all terms containing x to the left, all other terms to the right
-16x=29
x=29/-16
x=-1+13/16
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