5(x-3)=7x-(x+1)

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Solution for 5(x-3)=7x-(x+1) equation:



5(x-3)=7x-(x+1)
We move all terms to the left:
5(x-3)-(7x-(x+1))=0
We multiply parentheses
5x-(7x-(x+1))-15=0
We calculate terms in parentheses: -(7x-(x+1)), so:
7x-(x+1)
We get rid of parentheses
7x-x-1
We add all the numbers together, and all the variables
6x-1
Back to the equation:
-(6x-1)
We get rid of parentheses
5x-6x+1-15=0
We add all the numbers together, and all the variables
-1x-14=0
We move all terms containing x to the left, all other terms to the right
-x=14
x=14/-1
x=-14

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