5(x-3)=8-4(x-1)

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Solution for 5(x-3)=8-4(x-1) equation: 



5(x-3)=8-4(x-1)

We move all terms to the left:

5(x-3)-(8-4(x-1))=0

We multiply parentheses

5x-(8-4(x-1))-15=0



We calculate terms in parentheses: -(8-4(x-1)), so:

8-4(x-1)

determiningTheFunctionDomain
-4(x-1)+8

We multiply parentheses

-4x+4+8

We add all the numbers together, and all the variables

-4x+12

Back to the equation:

-(-4x+12)



We get rid of parentheses

5x+4x-12-15=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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