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5(x-3)=9(x-2)-5
We move all terms to the left:
5(x-3)-(9(x-2)-5)=0
We multiply parentheses
5x-(9(x-2)-5)-15=0
We calculate terms in parentheses: -(9(x-2)-5), so:We get rid of parentheses
9(x-2)-5
We multiply parentheses
9x-18-5
We add all the numbers together, and all the variables
9x-23
Back to the equation:
-(9x-23)
5x-9x+23-15=0
We add all the numbers together, and all the variables
-4x+8=0
We move all terms containing x to the left, all other terms to the right
-4x=-8
x=-8/-4
x=+2
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