5(x-4)(x+6)=0

Solution for 5(x-4)(x+6)=0 equation:

5(x-4)(x+6)=0

We multiply parentheses ..

5(+x^2+6x-4x-24)=0

We multiply parentheses

5x^2+30x-20x-120=0

We add all the numbers together, and all the variables

5x^2+10x-120=0

a = 5; b = 10; c = -120;
Δ = b2-4ac
Δ = 102-4·5·(-120)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*5}=\frac{-60}{10}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*5}=\frac{40}{10}
=4
$