5(x-4)+2=-3(x-2)-8

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Solution for 5(x-4)+2=-3(x-2)-8 equation: 



5(x-4)+2=-3(x-2)-8

We move all terms to the left:

5(x-4)+2-(-3(x-2)-8)=0

We multiply parentheses

5x-(-3(x-2)-8)-20+2=0



We calculate terms in parentheses: -(-3(x-2)-8), so:

-3(x-2)-8

We multiply parentheses

-3x+6-8

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

5x-(-3x-2)-18=0

We get rid of parentheses

5x+3x+2-18=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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