5(x-4)+2x+1=27

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Solution for 5(x-4)+2x+1=27 equation: 



5(x-4)+2x+1=27

We move all terms to the left:

5(x-4)+2x+1-(27)=0

We add all the numbers together, and all the variables

2x+5(x-4)-26=0

We multiply parentheses

2x+5x-20-26=0

We add all the numbers together, and all the variables

7x-46=0

We move all terms containing x to the left, all other terms to the right

7x=46

x=46/7

x=6+4/7

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