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5(x-4)+2x=6(x-3)
We move all terms to the left:
5(x-4)+2x-(6(x-3))=0
We add all the numbers together, and all the variables
2x+5(x-4)-(6(x-3))=0
We multiply parentheses
2x+5x-(6(x-3))-20=0
We calculate terms in parentheses: -(6(x-3)), so:We add all the numbers together, and all the variables
6(x-3)
We multiply parentheses
6x-18
Back to the equation:
-(6x-18)
7x-(6x-18)-20=0
We get rid of parentheses
7x-6x+18-20=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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