5(x-4)+2x=7(x+3)-41

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Solution for 5(x-4)+2x=7(x+3)-41 equation: 


Simplifying
5(x + -4) + 2x = 7(x + 3) + -41

Reorder the terms:
5(-4 + x) + 2x = 7(x + 3) + -41
(-4 * 5 + x * 5) + 2x = 7(x + 3) + -41
(-20 + 5x) + 2x = 7(x + 3) + -41

Combine like terms: 5x + 2x = 7x
-20 + 7x = 7(x + 3) + -41

Reorder the terms:
-20 + 7x = 7(3 + x) + -41
-20 + 7x = (3 * 7 + x * 7) + -41
-20 + 7x = (21 + 7x) + -41

Reorder the terms:
-20 + 7x = 21 + -41 + 7x

Combine like terms: 21 + -41 = -20
-20 + 7x = -20 + 7x

Add '20' to each side of the equation.
-20 + 20 + 7x = -20 + 20 + 7x

Combine like terms: -20 + 20 = 0
0 + 7x = -20 + 20 + 7x
7x = -20 + 20 + 7x

Combine like terms: -20 + 20 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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