5(x-4)+3(x+12)=0

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Solution for 5(x-4)+3(x+12)=0 equation: 



5(x-4)+3(x+12)=0

We multiply parentheses

5x+3x-20+36=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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