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5(x-4)+3=2x+3(-5+x)
We move all terms to the left:
5(x-4)+3-(2x+3(-5+x))=0
We add all the numbers together, and all the variables
5(x-4)-(2x+3(x-5))+3=0
We multiply parentheses
5x-(2x+3(x-5))-20+3=0
We calculate terms in parentheses: -(2x+3(x-5)), so:We add all the numbers together, and all the variables
2x+3(x-5)
We multiply parentheses
2x+3x-15
We add all the numbers together, and all the variables
5x-15
Back to the equation:
-(5x-15)
5x-(5x-15)-17=0
We get rid of parentheses
5x-5x+15-17=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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