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5(x-4)+4=2x+3(x+2)=-22
We move all terms to the left:
5(x-4)+4-(2x+3(x+2))=0
We multiply parentheses
5x-(2x+3(x+2))-20+4=0
We calculate terms in parentheses: -(2x+3(x+2)), so:We add all the numbers together, and all the variables
2x+3(x+2)
We multiply parentheses
2x+3x+6
We add all the numbers together, and all the variables
5x+6
Back to the equation:
-(5x+6)
5x-(5x+6)-16=0
We get rid of parentheses
5x-5x-6-16=0
We add all the numbers together, and all the variables
-22!=0
There is no solution for this equation
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