5(x-4)+4=4(x+3)+x

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Solution for 5(x-4)+4=4(x+3)+x equation: 



5(x-4)+4=4(x+3)+x

We move all terms to the left:

5(x-4)+4-(4(x+3)+x)=0

We multiply parentheses

5x-(4(x+3)+x)-20+4=0



We calculate terms in parentheses: -(4(x+3)+x), so:

4(x+3)+x

We add all the numbers together, and all the variables

x+4(x+3)

We multiply parentheses

x+4x+12

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We add all the numbers together, and all the variables

5x-(5x+12)-16=0

We get rid of parentheses

5x-5x-12-16=0

We add all the numbers together, and all the variables

-28!=0

There is no solution for this equation

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