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5(x-4)+7=2x+3(-4+x)
We move all terms to the left:
5(x-4)+7-(2x+3(-4+x))=0
We add all the numbers together, and all the variables
5(x-4)-(2x+3(x-4))+7=0
We multiply parentheses
5x-(2x+3(x-4))-20+7=0
We calculate terms in parentheses: -(2x+3(x-4)), so:We add all the numbers together, and all the variables
2x+3(x-4)
We multiply parentheses
2x+3x-12
We add all the numbers together, and all the variables
5x-12
Back to the equation:
-(5x-12)
5x-(5x-12)-13=0
We get rid of parentheses
5x-5x+12-13=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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