5(x-4)+x=6(x-2)-8

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Solution for 5(x-4)+x=6(x-2)-8 equation:


Simplifying
5(x + -4) + x = 6(x + -2) + -8

Reorder the terms:
5(-4 + x) + x = 6(x + -2) + -8
(-4 * 5 + x * 5) + x = 6(x + -2) + -8
(-20 + 5x) + x = 6(x + -2) + -8

Combine like terms: 5x + x = 6x
-20 + 6x = 6(x + -2) + -8

Reorder the terms:
-20 + 6x = 6(-2 + x) + -8
-20 + 6x = (-2 * 6 + x * 6) + -8
-20 + 6x = (-12 + 6x) + -8

Reorder the terms:
-20 + 6x = -12 + -8 + 6x

Combine like terms: -12 + -8 = -20
-20 + 6x = -20 + 6x

Add '20' to each side of the equation.
-20 + 20 + 6x = -20 + 20 + 6x

Combine like terms: -20 + 20 = 0
0 + 6x = -20 + 20 + 6x
6x = -20 + 20 + 6x

Combine like terms: -20 + 20 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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