5(x-4)-(4x-5)=5(2x+5)-22

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Solution for 5(x-4)-(4x-5)=5(2x+5)-22 equation: 



5(x-4)-(4x-5)=5(2x+5)-22

We move all terms to the left:

5(x-4)-(4x-5)-(5(2x+5)-22)=0

We multiply parentheses

5x-(4x-5)-(5(2x+5)-22)-20=0

We get rid of parentheses

5x-4x-(5(2x+5)-22)+5-20=0



We calculate terms in parentheses: -(5(2x+5)-22), so:

5(2x+5)-22

We multiply parentheses

10x+25-22

We add all the numbers together, and all the variables

10x+3

Back to the equation:

-(10x+3)



We add all the numbers together, and all the variables

x-(10x+3)-15=0

We get rid of parentheses

x-10x-3-15=0

We add all the numbers together, and all the variables

-9x-18=0

We move all terms containing x to the left, all other terms to the right

-9x=18

x=18/-9

x=-2

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